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Bash Syntax Error Bad For Loop Variable

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PS. Join them; it only takes a minute: Sign up bash script - can't get for loop working up vote 3 down vote favorite Background Info: I'm trying to follow the example Forum Operations by The UNIX and Linux Forums ≡ Menu Home Free eBook Start Here Contact About 12 Bash For Loop Examples for Your Linux Shell Scripting by Ramesh Natarajan on However the variable j start with 5, and getting increment by 5 every time the loop gets executed. $ cat for10.sh for ((i=1, j=10; i <= 5 ; i++, j=j+5)) do this contact form

varname is any Bash variable name. If you have an older version you can use instead of {START..END..INCREMENT} the command $(seq START INCREMENT END) in the for loop. Adv Reply Quick Navigation Programming Talk Top Site Areas Settings Private Messages Subscriptions Who's Online Search Forums Forums Home Forums The Ubuntu Forum Community Ubuntu Official Flavours Support New to In ash, you would need to write¹: day=5 while [ $day -lt 367 ]; do … day=$((day + 5)) done Note that depending on the Linux distribution, /bin/sh is either ash

Syntax Error Bad For Loop Variable Shell

Browse other questions tagged bash dash ash for or ask your own question. You have the right header so now the 'sh' bit you were using to attempt to run it with is not needed. The following example adds "(WEEKEND)" to Sat and Sun, and "(weekday)" to rest of the days. $ cat for7.sh i=1 for day in Mon Tue Wed Thu Fri Sat Sun do I'm running version 4,2,25(1) I also tried using C like syntax where you do for (i=0;i<=8;i++) but that doesn't work either.

asked 2 years ago viewed 9182 times active 1 month ago Related 0How to give loop variable i in the cut command?1Providing input for while loop1While Loop Syntax Error-1How to stop Tango Icons Tango Desktop Project. Output is comming as follows….. Bash Syntax Error Invalid Arithmetic Operator Password Home Search Forums Register Forum RulesMan PagesUnix Commands Linux Commands FAQ Members Today's Posts Shell Programming and Scripting Unix shell scripting - KSH, CSH, SH, BASH, PERL, PHP, SED, AWK

So try either PHP Code: #!/bin/bash
for((i=0;i<=4

Browse other questions tagged scripts or ask your own question. Bash Syntax Error Near Unexpected Token Then' Can you help with this problem? I'm running on ubuntu 12 EDIT 2 Ok... I also tried: #!/bin/bash for ((i=0;i<9;i++)); do echo "i is $i" tmpdate=$(date -d "$i days" "+%b %d") echo $tmpdate done And that gives me the error: test.sh: 4: test.sh: Syntax error:

Bash Syntax Error Near Unexpected Token Done'

Problem with using pause and onslide in one frame Now I know my ABCs, won't you come and golf with me? Problem? Syntax Error Bad For Loop Variable Shell Why are some programming languages Turing complete but lack some abilities of other languages? Bash Syntax Error Near Unexpected Token Else' very thanks in advance Link mathison April 15, 2013, 12:59 pm Im trying to run each comand then the next one in a loop.

I have tried doing what the answer to this question tells, but it produces this error: Syntax error: Bad for loop variable My OS is Ubuntu 12.04 and the code looks weblink vBulletin 2000 - 2016, Jelsoft Enterprises Ltd. How to make different social classes look quite different? This is the concept that is used in the above for5.sh example. Bash Syntax Error Near Unexpected Token Fi'

Why can a Gnome grapple a Goliath? Replace #!/bin/sh with #!/bin/bash to make the shebang work. This is my script #!/bin/bash for (( c=1; c<=5; c++ )) do echo "Welcome $c times..." done can any one tell me syntax for for loop in sh(in ubuntu it links navigate here Link Aashish June 16, 2014, 4:40 pm Below code executed successfull but output will be not generated..

Not the answer you're looking for? Bash Syntax Error Near Unexpected Token Do' ls -l /bin/bash, maybe ? –Costi Ciudatu Apr 11 '11 at 20:37 1 This works for me when you put the done statement on its own line. –Amir Afghani Apr Any help please?

You can get similar behavior in the standard POSIX shell using for c in $(seq 1 5) share|improve this answer edited Apr 12 '11 at 1:29 answered Apr 11 '11 at

Intuition behind Harmonic Analysis in Analytic Number Theory Is it possible to check for existence of member template just by identifier? for num in {1..10..2} Link Pier July 12, 2011, 2:05 pm thanks Ramesh, I knew the "classic" bash syntax (but it is always good to pop up some old knowledge) but Note: you want to echo $i. Bash Syntax Error Near Unexpected Token Newline' The current item from the list will be stored in a variable "varname" each time through the loop.

Where is it wrong. I always like your articles. so now that I'm being careful to make sure that I invoke the script the right way... his comment is here when defined as an sh script and i execute using sh, the C-style version fails [email protected]:~/tmp/test$ sh test.sh test.sh: 5: test.sh: Syntax error: Bad for loop variable when defined as an

Doesn't sh run a bash script? –Krøllebølle Oct 26 '12 at 10:54 @Krøllebølle The Bourne shell (sh) has a different syntax for for loops. while : do sleep $i echo “Number: $((i++))” done Link Ken Butcher July 18, 2011, 11:16 am For those using Ubuntu, be aware that Dash is the symbolic link for sh Natural construction What to tell to a rejected candidate? The time now is 02:04 AM.

How to extrude a face parallel to another? scripts share|improve this question edited Jan 6 '14 at 11:58 Florian Diesch 46.7k12105131 asked Jan 6 '14 at 11:56 Gaurav Rai 814 add a comment| 2 Answers 2 active oldest votes Can Customs make me go back to return my electronic equipment or is it a scam? How to deal with a very weak student?

Not the answer you're looking for? Tweet >Add your comment If you enjoyed this article, you might also like.. 50 Linux Sysadmin Tutorials 50 Most Frequently Used Linux Commands (With Examples) Top 25 Best Linux Performance Is there a good way to get from Levoča to Lviv? Code: #!/bin/sh # Beep ip address trough internal pc speaker # Tested on Debian Linux @NSLU2 # Author: Sebastiaan Giebels, 2007 # Retreive dot-separated ipv4 address from the ifconfig information, using

Thanks! –Ziyaddin Sadigov Feb 26 '14 at 18:48 1 i=0; while [ $i -le 5 ]; do echo $i; i=$((i+1)); done –Florian Diesch Feb 26 '14 at 19:32 add a You can also simply drop me a line to say hello!. You need to press Ctrl-C to stop the loop. $ cat for9.sh i=1; for (( ; ; )) do sleep $i echo "Number: $((i++))" done Like we said above, press Ctrl-C So sayeth the Shepherd GTIN validation Verbs of buttons on websites How could banks with multiple branches work in a world without quick communication?

If you leave the keyword "in" without any values, it will not use the positional parameter as shown below. There are few exceptions to this best practice rule.